LENOVO笔试题

1．设计函数 int atoi(char *s)。

int atoi(char *s)

{

     char sign;

     char sign_val = 1;

     int val = 0;

     int n = 0;

     /* skip spaces */

     while (isspace(*s))

         ++s;

     if (*s == '-' || *s == '+')

         /* skip '-' and '+' sign */

     {

         sign = *s;

         if (sign == '-')

             sign_val = -1;

         ++s;

     }

     /* when goes here, it is not space or sign */

     while ((*s != '\0') && isdigit(*s))

     {

         val = 10 * n + (*s - '0');

         n = val;

         s++;

     }

     if (*s != '\0')

     {

         printf("non digit in your input!!\n");

         exit(-1);

     }

     /* non error occured */

     return (sign_val * val);

}

2．int i=(j=4,k=8,l=16,m=32); printf("%d", i); 输出是多少？

结果为: 32.