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位域的规律题


有无unsigned、a:1 a:2 a:4 a:8 a:16 a:32 以及用char的各值来试验就可发现位域的规律。


 #include <iostream>


  #include <windows.h>


  using namespace std;


  void main()


  {


  struct test


  {


  //在这里测试就可以发现其规律,有无unsigned、a:1 a:2 a:4 a:8 a:16 a:32 以及用char的各值来试验就可发现位域的规律


  unsigned int a:8;


  };


  test t1;


  t1.a = 0;


  cout<<"十进制 -> 0: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 0: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 1;


  cout<<"十进制 -> 1: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 1: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 2;


  cout<<"十进制 -> 2: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 2: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 3;


  cout<<"十进制 -> 3: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 3: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 126;


  cout<<"十进制 -> 126: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 126: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 127;


  cout<<"十进制 -> 127: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 127: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 128;


  cout<<"十进制 -> 128: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 128: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 129;


  cout<<"十进制 -> 129: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 129: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 253;


  cout<<"十进制 -> 253: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 253: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 254;


  cout<<"十进制 -> 254: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 254: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 255;


  cout<<"十进制 -> 255: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 255: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 256;


  cout<<"十进制 -> 256: "<<dec<<t1.a<<endl;


  cout<<"十六进制-> 256: "<<hex<<t1.a<<endl;


  cout<<endl;


  t1.a = 257;

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